Question

factorise z²+13z+40​

Answer 1

Answer:

In the given polynomial

z^2 +13z+40,

The first term is z^2  and its coefficient is 1.

The middle term is 13z and its coefficient is 13.

The last term is a constant term 40.

Multiply the coefficient of the first term by the constant 1×40=40.

We now find the factor of 40 whose sum equals the coefficient of the middle term, which is 13 and then factorize the polynomial z^2 +13z+40 as shown below:

z^2 +13z+40

=z^2 +8z+5z+40

=z(z+8)+5(z+8)

=(z+5)(z+8)

Hence, z^2 +13z+40=(z+5)(z+8).

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Answer 2

Answer:

z^2+13z+40

=z^2+8z+5z+40

=z (z+8)+5(z+8)

=(z+8)(z+5)