Question

factorise .z²-4z-12.​

Answer 1

Answer:

Step-by-step explanation:

(z+2)(z-6)

Answer 2

Step-by-step explanation:

${z}^{2} - 4z - 12 = 0\\ = {z}^{2} - 6 z+ 2z - 12 = 0 \\ = z(z - 6) + 2(z - 6) = 0 \\ = (z - 6)(z + 2) = 0 \\ z - 6 = 0 \: \: \: or \: \: \: z + 2 = 0 \\ z = 6 \: \: \: or \: \: \: z = - 2$

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