Question

Factorise1-2a-2b-3(a+b) ^2​

Answer 1

Step-by-step explanation:

=1-2a-2b-3(a+b)^

=1-2(a+b)-3(a+b)^

=1-3(a+b)+(a+b)-2(a+b)^

=1[1-3(a+b)]+(a+b)[1-3(a+b)]

=[1-3(a+b)] [1+(a+b)]

=(1-3a-3b) (1+a+b)

hope this will be helpful for you

Answer 2

ANSWER:-

1-2a -2b -3(a+b)²

= 1-2(a+b)-3(a+b)²

=1- 3(a+b) +(a+b) -3(a+b)²

=1[1-3(a+b)]+(a+b)[1-3(a+b)]

=[1-3(a+b)][1+(a+b)]

=(1-3a-3b)(1+a+b)

EXPLANATION:-

• We have written - 2a - 2b as - 2(a+b)

• We wrote - 2(a+b) as = - 3(a+b)+(a+b) based on the fact, - 3 +1 = - 2

• Then 1, a+b are taken as common from the first 2, last 2 terms respectively.

• Next we simplified to get [1 - 3 a - 3 b] [1 + a + b]