factorise1 + x + xy + x^2y
Answers
Answered by
2
Step-by-step explanation:
x²Y+xy+x+1=0
xy(x+1)+1(x+1)=0
x=-1
xy=-1
y=1 OK friend this is urs answer
Answered by
0
Answer:
Step-by-step explanation:
x^2-y^2-2y-1
=x^2-(y^2+2y+1)
=x^2-(y^2+2•y•1+1^2)
=x^2-(y+1)^2
=[x+(y+1)][x-(y+1)]
=[x+y+1][x-y-1]
Hope it helps
;)
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