Math, asked by sunandakharatmol86, 5 months ago

factorise125ycube-1​

Answers

Answered by Anonymous
4

Answer:

5(5y)^3 -1

i am not sure but hope this helps you

Answered by xInvincible
1

125 {y}^{3}  - 1 \\  =  > (5y {)}^{3}  - (1 {)}^{3}  \\  =  > \bf  \color{purple}{ {a}^{3}  -  {b}^{3}  = (a - b)( {a}^{2}  + ab +  {b}^{2)} } \\  =  >  \bf{lets \: put \: the \: values} \\  =  > (5y - 1)((5y {)}^{2}  + (5y \times 1) + ( {1)}^{2} ) \\  =  >  \boxed{(5y - 1)(25 {y}^{2} + 5y + 1) }

Hope it helped

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