Factorise4(x+y)^2-3(x+y)
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Here is ur answer
4(x+y)²-3(x+y)
(x+y)[4(x+y)-3]
(x+y)[4x+4y-3]
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Answered by
2
= 4(x+y)²-3(x+y)
= (x+y)[(4(x+y)-3]
=(x+y) [4x+4y-3]
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