Question

factorise64/125a^3-96/25a^2+48/5a-8

Answer 1

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Formula to be used
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( x - y) ³ = x³ - 3x²y +3xy² +y³
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$= > \: \: \frac{64}{125} {a}^{3} - \frac{96}{25} {a}^{2} + \frac{48}{5} a - 8 \\ \\ = {( \frac{4}{5}a) }^{3} - 3 \times {( \frac{4}{5}a) }^{2} \times 2 + 3 \times \frac{4}{5} a \times {(2)}^{2} - {(2)}^{3} \\ \\ = {( \frac{4}{5}a - 2) }^{3} \\ \\ = \frac{8}{125} (2a - 5) ^{3}$
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Answer 2

Answer:

$\frac{64}{125} {a}^{3} - \frac{96}{25} {a}^{2} + \frac{48}{5} a - 8$

$= ( \frac{4}{5} a)^{3} - 3 {( \frac{4}{5}a )}^{2} \times 2 + 3 \: \: \frac{4}{5} a \times (2) ^{2}$

$= {( \frac{4}{5} a - 2)}^{3}$

$= {( \frac{4}{5} a - 2)}{( \frac{4}{5} a - 2)}{( \frac{4}{5} a - 2)}$

Step-by-step explanation:

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