factorise6x2+16x+10
Answers
Answer:
Step by Step Solution:
(1): "x2" was replaced by "x^2".
STEP
1
:
Equation at the end of step 1
((2•3x2) - 16x) + 10
STEP
2
:
STEP
3
:
Pulling out like terms
3.1 Pull out like factors :
6x2 - 16x + 10 = 2 • (3x2 - 8x + 5)
Trying to factor by splitting the middle term
3.2 Factoring 3x2 - 8x + 5
The first term is, 3x2 its coefficient is 3 .
The middle term is, -8x its coefficient is -8 .
The last term, "the constant", is +5
Step-1 : Multiply the coefficient of the first term by the constant 3 • 5 = 15
Step-2 : Find two factors of 15 whose sum equals the coefficient of the middle term, which is -8 .
-15 + -1 = -16
-5 + -3 = -8 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -5 and -3
3x2 - 5x - 3x - 5
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (3x-5)
Add up the last 2 terms, pulling out common factors :
1 • (3x-5)
Step-5 : Add up the four terms of step 4 :
(x-1) • (3x-5)
Which is the desired factorization
Final result :
2 • (3x - 5) • (x - 1)
Answer:
ans.
= 6x^2 + 10 x + 6x +10 = 0
= 6x( x + 10 ) + 1( 6x + 10 ) =0
= ( 6x +1 ) ( 6x + 10 ) = 0
= x = -1/6 , -10/6 {ans }