Math, asked by ariyansharma77pax8dc, 1 year ago

factorise8x³+y³+27z³-18xyz

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Answered by 123lokendra
2
Using Identity a³+ b³+ c³- 3abc =  (a+b+c) (a²+b²+c²-ab-bc-ca)8x³+y³+27z³-18xyz = (2x)³+(y)³+(3z)³ { (2x)²+(y)²+(3z)² -(2x)(y) -(y)(3z) -(3z)(2x)}Therfore, factorisation of 8x³+y³+27z³-18xyz = (2x)³+(y)³+(3z)³ { (2x)²+(y)²+(3z)² -(2x)(y) -(y)(3z) -(3z)(2x)}
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Answered by 27jenny
0
I hope it helps u ...
i am not sure....
it may be wrong....
if it is helpful for you plz mark me brainliest
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