factorise8x³+y³+27z³-18xyz
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Using Identity a³+ b³+ c³- 3abc = (a+b+c) (a²+b²+c²-ab-bc-ca)8x³+y³+27z³-18xyz = (2x)³+(y)³+(3z)³ { (2x)²+(y)²+(3z)² -(2x)(y) -(y)(3z) -(3z)(2x)}Therfore, factorisation of 8x³+y³+27z³-18xyz = (2x)³+(y)³+(3z)³ { (2x)²+(y)²+(3z)² -(2x)(y) -(y)(3z) -(3z)(2x)}
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it may be wrong....
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