Question

Factorised form of 7a⁴ - 7b⁴ is _________.​

Answer 1

Answer:

The answer is $7(a-b)(a+b)(a^2+b^2)$

Step-by-step explanation:

  $7a^4-7b^4$

$=7(a^4-b^4)$, factor out 7

$=7[(a^2)^2-(b^2)^2]$, write in the form of $x^2-y^2$

$=7(a^2-b^2)(a^2+b^2)$, use $x^2-y^2=(x-y)(x+y)$

$=7(a-b)(a+b)(a^2+b^2)$, again use above identity