. factorised the polynomial
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Let p(x) =x^3+13x^2 +32x+20
Using hit and trial method
x=-1
P(-1)=-1^3 +13×(-1)^2 +32×(-1)+20
=-33+33
=0
So, x+1is a factor of p(x) [by factor theorem]
To find other factors we must divide p(x) by x+1
And the other factor found is x^2 +12x+10
Factorising x^2 +12x+10
=x(x+10)+2(x+10)
=(x+2)(x+10)
So polynomial p(x) would be factorised as (x+1),(x+2),(x+10)..
Thats the answer Plz try to mark as brainliest and goodbyeee
Using hit and trial method
x=-1
P(-1)=-1^3 +13×(-1)^2 +32×(-1)+20
=-33+33
=0
So, x+1is a factor of p(x) [by factor theorem]
To find other factors we must divide p(x) by x+1
And the other factor found is x^2 +12x+10
Factorising x^2 +12x+10
=x(x+10)+2(x+10)
=(x+2)(x+10)
So polynomial p(x) would be factorised as (x+1),(x+2),(x+10)..
Thats the answer Plz try to mark as brainliest and goodbyeee
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