Factorised x³-3x²+3x+7 by factor theorem method
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Answered by
0
hey user here's ur answer :-)
x3+3x2+3x-7
=x3+3.x2.1+3.x.12+13-8
=(x+1)3-(2)3
=(x+1-2){(x+1)2+2.(x+1)+22}
=(x-1)(x2+2x+1+2x+2+4)
=(x-1)(x2+4x+7)
hope it helps
x3+3x2+3x-7
=x3+3.x2.1+3.x.12+13-8
=(x+1)3-(2)3
=(x+1-2){(x+1)2+2.(x+1)+22}
=(x-1)(x2+2x+1+2x+2+4)
=(x-1)(x2+4x+7)
hope it helps
BrainlyQueen01:
or better u can check the question asked by me bcoz i have also asked this question earlier
U have done differently bcz in my question sign of 7 is positive but ur it's 7 negative se ur ans
srry
can u kindly change ur sign plzz
(x+1)(x^2-4x+7)
Answered by
0
x+1=0;x=-1;
x³-3x²+3x+7
(-1)³-3*(-1)²+3*(-1)+7
-1-3-3+7
-4+4= 0
making more factors of it...(dividing it so pls don't be confused over signs)
X+1√ x³-3x²+3x+7 ] x²-4x+7
x³+x²
_ _ _ _ _ _
0-4x²+3x
-4x²- 4x
_ _ _ _ _ _ _ _
7x+7
7x+7
_ _ _ _ _ _ _ _ _
0
x²-4x+7( sorry I don't know why I solution is not given...or not coming ...maybe this is not asked ..or this is the only answer (X+1)(x²-4x+7))
x³-3x²+3x+7
(-1)³-3*(-1)²+3*(-1)+7
-1-3-3+7
-4+4= 0
making more factors of it...(dividing it so pls don't be confused over signs)
X+1√ x³-3x²+3x+7 ] x²-4x+7
x³+x²
_ _ _ _ _ _
0-4x²+3x
-4x²- 4x
_ _ _ _ _ _ _ _
7x+7
7x+7
_ _ _ _ _ _ _ _ _
0
x²-4x+7( sorry I don't know why I solution is not given...or not coming ...maybe this is not asked ..or this is the only answer (X+1)(x²-4x+7))
Yes my also same is being happen
pls do mark it as the brainliest
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