Math, asked by vishalavaid8899, 2 months ago

factorisewthe expression and divide them as as directed 36ab(2b+3)(2b-3)÷4b (2b+3)​

Answers

Answered by arvindmishra69
1

Step-by-step explanation:

mad

Answered by pulakmath007
9

SOLUTION

TO DETERMINE

To Factorise the expression and divide them as as directed

36ab(2b+3)(2b-3) ÷ 4b (2b+3)

EVALUATION

Here two given expressions are

36ab(2b+3)(2b-3) and 4b(2b+3)

First expression

= 36ab(2b+3)(2b-3)

= 2 × 2 × 3 ×3 × a × b × (2b+3)(2b-3)

Second expression

4b(2b+3)

= 2 × 2 × (2b+3)

Hence the required result

  \displaystyle \sf{ =  \frac{36ab(2b + 3)(2b - 3)}{4b(2b + 3)} }

  \displaystyle \sf{ =  \frac{2 \times 2 \times 3 \times 3 \times a \times b \times (2b + 3) \times (2b - 3)}{2 \times 2 \times b \times (2b + 3)} }

= 3 × 3 × a × ( 2b - 3 )

= 9a( 2b - 3 )

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