factorisex^3-27 plzz help me to find out this problem
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Hi ,
*************************
We know the algebraic identity ,
a³ - b³ = ( a - b )( a² + ab + b² )
*****************************
Now ,
x³ - 27
= x³ - 3³
= ( x - 3 )( x² + x × 3 + 3² )
= ( x - 3 ) ( x² + 3x + 9 )
I hope this helps you.
: )
*************************
We know the algebraic identity ,
a³ - b³ = ( a - b )( a² + ab + b² )
*****************************
Now ,
x³ - 27
= x³ - 3³
= ( x - 3 )( x² + x × 3 + 3² )
= ( x - 3 ) ( x² + 3x + 9 )
I hope this helps you.
: )
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