Question

factorising difference of two squares​

Answer 1

Answer:

(5+x) (5-x) , (7p+4) (7p-4( , (b^2+a) (b^2-a)

Step-by-step explanation:

1] 25-x^2

5^2-x^2(a^2-b^2=(a+b)(a-b))

= (5+x) (5-x)

2] 49p^2-16

= 7p^2-4^2(a^2-b^2=(a+b)(a-b))

= (7p+4) (7p-4(

3] b^4-a^2

= (b^2) ^2-a^2(a^2-b^2=(a+b)(a-b))

= (b^2+a) (b^2-a)

I hope my answer helps you☺☺

Answer 2

Answer: Solved Below

Step-by-step explanation:

Soving using the identity, $a^{2} -b^{2} = (a+b)(a-b)$

1) 25 - $x^{2}$ =  $5^{2} -x^{2}$

               =$(5+x)(5-x)$

2)49$p^{2}$- 16= $(7p)^{2} - 4^{2}$

                = $(7p+4)(7p-4)$

3)$b^{4} - a^{2}$ = $(b^{2})^{2} - a^{2}$

               = $(b^{2} +a)(b^{2} -a)$

ThanK U : )