Question

factorising expression by grouping 6-2y+xy-3x​

Answer 1

6-2y+xy-3x

=xy-3x-2y+6

=x(y-3)-2(y-3)

=(x-2)(y-3)

SO,

x-2=0 or y-3=0

x=2 y=3

I HOPE YOU WILL MARK ME AS BRAINLIEST ❤

Answer 2

Answer:

( x - 2 ) ( y - 3 )

Step-by-step explanation:

6-2y+xy-3x​

Group

- 3x + xy - 2y + 6

Factorize

x( -3 + y ) - 2 ( y - 3 )

( x - 2 ) ( y - 3 )

Hope this helps.