Question

factorising expression by grouping a-ab+b-b²​

Answer 1

Answer:

a(1-b)+b(1-b)

(1-b)(a+b)

hope it helps

Answer 2

Answer:

the zeros of the p(X)=a-ab+b-b^2

are= -b and 1

Step-by-step explanation:

a-ab+b-b^2

a(1-b)+b(1-b)

(a+b) (1-b)

the zeros are= a+b=0 1-b=0

a=-b. -b=-1

b=1(-1and-1get

cancelled)