Question

Factorising with HCF and regrouping-
(6a-5b)²-9(a-2b)²

Answer 1

Answer:

Step-by-step explanation:

(6a-5b)²-9(a-2b)²

(6a-5b)²-(3a-6b)²  (9 = 3² multiply each term by 3)

(6a-5b+3a-6b)(6a-5b-3a+6b)  [a²-b²=(a+b)(a-b)]

(9a-11b)(3a+b)