Factorixe:-
a^2.b^2+2b(a^2+1)+a^2-b^2-1
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Answer:
Distribute
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a^{2}b^{2}+{\color{#c92786}{2b(a^{2}+1)}}+a^{2}-1b^{2}-1
a2b2+2b(a2+1)+a2−1b2−1
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a^{2}b^{2}+{\color{#c92786}{2ba^{2}+2b}}+a^{2}-1b^{2}-1
a2b2+2ba2+2b+a2−1b2−1
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Rearrange terms
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{\color{#c92786}{a^{2}b^{2}+2ba^{2}+2b+a^{2}-b^{2}-1}}
a2b2+2ba2+2b+a2−b2−1
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{\color{#c92786}{a^{2}b^{2}+2ba^{2}+a^{2}-b^{2}+2b-1}}
a2b2+2ba2+a2−b2+2b−1
Solution
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a^{2}b^{2}+2ba^{2}+a^{2}-b^{2}+2b-1
a2b2+2ba2+a2−b2+2b−1
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