Question

factorixe this problem
$192 {a}^{3} + 3$
​

Answer 1

Solution:

$192 {a}^{3} + 3$

=$3(64 {a}^{3} + 1)$

=3[(4a)³+1³]

= 3[(4a+1){(4a)²-(4a)×1+1²}]

=3[(4a+1){16a²-4a+1}]

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