factoriz x2-6x+9 plz solve by explsining
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Answered by
10
hey your ans is here
_________
given:-
x2-6x+9
now taking out the factors we get
x2-3x-3x+9
group them
(x2-3x)-(3x+9)
x(x-3)-3(x-3)
(x-3)(x-3)
(x-3)2
remember the factors must be as such that the by there multiplication last no should be formed and by there addition the middle one
__________
_________
given:-
x2-6x+9
now taking out the factors we get
x2-3x-3x+9
group them
(x2-3x)-(3x+9)
x(x-3)-3(x-3)
(x-3)(x-3)
(x-3)2
remember the factors must be as such that the by there multiplication last no should be formed and by there addition the middle one
__________
Answered by
1
Factors of 9 are 3x3
x2-3x-3x+6=0
x(x-3)-3(x-3)=0
(x-3)(x-3)
x=3
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