Math, asked by hugocarrillo28, 1 year ago

Factorización de una Diferencia de Cuadrado

64m^10 - 36n^18=

Answers

Answered by veerendrakumaruppu
2
64m^10 - 36n^18

= (8m^5)^2 - (6n^9)^2

= (8m^5 + 6n^9)(8m^5- 6n^9)

=2*(4m^5 + 3n^9)*2*(4m^5- 3n^9)

= 4*(4m^5 + 3n^9)*(4m^5- 3n^9) ——> Answer
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