factorization 2x^2-7x=39
Answers
Answered by
5
2x^2 - 7x - 39
= 2x^2 -13x + 6x - 39
= x (2x - 13) + 3 (2x - 13)
= (x+3) (2x-13)
Answered by
3
Answer:
Hey mate here is your answer..
2x^2-7x=39
or, 2x^2-7x-39=0
or, 2x^2+6x-13x-39=0
or, 2x(x+3)-13(x+3)
or, (x+3) (2x-13)
Hope this will help you...
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