Question

factorization
2y^2-5y+2​

Answer 1

Answer:

$2 {y}^{2} - 5y + 2 = 0 \\ = 2y {}^{2} - 4y - y + 2 = 0 \\ = 2y(y - 2) - 1(y - 2) = 0 \\ = (y - 2)(2y - 1) = 0 \\ = y = 2 \: \: and \: \: \frac{1}{2}$

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Answer 2

$\huge\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\pink{R}}}}$

=>2y^2-5y+2

=>2y^2-y-4y+2

=>y(2y-1)-2(2y-1)

=>(y-2)(2y-1)