Question

Factorization 32(x+y)^ 2 - 2x-2y​

Answer 1

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$= (32 (x + y)^2 - 2x) - 2y$

$= 32x^2 + 64xy - 2x + 32y^2 - 2y$

$= (16x^2 + 32xy - x + 16y^2 - y)$

$= (16x^2 + 32xy - x + 16y^2 - y)$

Answer 2

Answer:

$\longrightarrow\sf{(32[x+y]^2-2x) -2y} \\ \\ \longrightarrow\sf{32x^2 + 64xy - 2x + 32y^2 - 2y} \\ \\ \longrightarrow\sf{(16x^2 + 32xy - x + 16y^2 - y)}$

❍ Hope it will be helpful ✌️