factorization 36a^2 + 12abc+ 15b^2c^2
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Answer:
36a² + 12abc + 15 b² c²
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Answered by
9
Answer:
Here, coefficient of a2 = 36, coefficient of a = 12bc and constant term = - 15b2c2
We shall now split up the coefficient of middle term i.e., 12bc into two parts whose sum is 12bc and product is 36 (-15b2c2) = - 500b2c2
So, we replace middle term 12abc = 30abc – 18abc
Thus, we have
36a2 –12abc– 15b2c2 = 36a2 + 30abc – 18abc – 15b2c2
= (6a + 5bc) (6a – 3bc)
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