Question

factorization (4x²+25y²-16z²+20zy-40yz-16zx)​

Answer 1

Answer:

we can use the identity $[a+b-c]^2=a^2+b^2+^2+2ab-2bc-2ca$

Here the a is $4x^2=[2x]^2$ , b is $25y^2=[5y]^2$ and c is $16z^2=[4z]^2$.Now we should include the values

$[2x]^2+[5y]^2+[4z]^2+2*2x*5y-2*5y*4z-2*2x*4z$

Therefore,$[2x+5y-4z]^2$