factorization
6xy2+9x2y-24xy
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Answered by
2
Answer:
9 x² y - 24 x y² - 16 y³
= y (9 x² - 24 xy - 16 y² ) = y [ (3 x - 4y)² - 32 y² ]
= y (3x - 4y + √32 y) (3x-4y - √32 y) √32 = 4√2
= y [ 3x + 4(√2-1)y ] [ 3x - 4(√2+1)y ]
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Answered by
1
Answer:
3xy (2y + 3x - 8)
the H.C.F of 6xy^2, x^2y, -24xy is 3xy
thus we put 3xy outside the bracket and the rest within the bracket
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