Question

factorization 9ײ+15×-6​

Answer 1

Answer:

3(3x-1)(x+2)

Step-by-step explanation:

=3(3$x^{2}$+5x-2)

=3(3$x^{2}$+6x-x-2)

=3{3x(x+2)-(x+2)}

=3(3x-1)(x+2)

Hope this helps :)

Answer 2

Answer:

9x ^2 - 15x + 6

so we have to find two numbers whose multiplying gives 54 and addition gives 15

${9x}^{2} - 15x + 6$

${9x}^{2} - 9x - 6x + 6$

$9x(x - 1) \: \: - 6(x - 1)$

$(9x - 6) \: \: (x \: - 1)$

$(9x - 6) \: \: = \\ \\ x = 6 \div 9$

X = 6 / 9

$(x - 1) \\ \\ \\ x \: = 1$

so the value of X = 1

and X = 6/ 9