Question

Factorization method
Solve the following quadratic equation
X square + 5 x minus 6 equals to zero

Answer 1

Answer:

x=-6,1

Step-by-step explanation:

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Answer 2

Answer:

x = 1,-6

Given :

quadratic equation = x² + 5x - 6 = 0

To find :

zeroes of the quadratic equation

Solution :

Given quadratic equation,

x² + 5x - 6

To solve it using factorization method,

we must know the sum - product pattern

x² + 5x - 6

=> It is of the form ax² + bx + c

Find the product of quadratic term [ax²] and constant term [c]

= x² × (-6)

= -6x²

Now, find the factors of "-6x²" in pairs

\begin{gathered}= > x \times (-6x) \\\\ = > -x \times 6x \\\\ = > 2x \times -3x \\\\ = > -2x \times 3x \\\\\end{gathered}

=>x×(−6x)

=>−x×6x

=>2x×−3x

=>−2x×3x

Now, from the above, find the pair that adds to get linear term [bx]

6x - x = 5x

So, split 5x into 6x and -x

x² + 5x - 6 = 0

x² - x + 6x - 6 = 0

Find the common factor,

x(x - 1) + 6(x - 1) = 0

(x - 1)(x + 6) =0

=> x - 1 = 0 ; x = 1

=> x + 6 = 0 ; x = -6

Step-by-step explanation:

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