Question

factorization of 16² - 4b² is ??​

Answer 1

Required Answer:-

Given to factorise:

• 16² - 4b²

Solution:

$\sf 16 {}^{2} - 4 {b}^{2}$

$\sf = {(16)}^{2} - {(2b)}^{2}$

$\sf = (16 + 2b)(16 - 2b)$

$\sf = 2(8 + b) \times 2(8 - b)$

$\sf = 4(8 + b)(8 - b)$

Hence, the factorised form is 4(8 + b)(8 - b)

Identity Used:

• $\sf {x}^{2} - {y}^{2} = (x + y)(x - y)$

Other Identities:

• $\sf {a}^{2} + 2ab + {b}^{2} = {(a + b)}^{2}$
• $\sf {a}^{2} - 2ab + {b}^{2} = {(a - b)}^{2}$
• $\sf {a}^{3} + {b}^{3} = (a + b)( {a}^{2} - ab + {b}^{2} )$
• $\sf {a}^{3} - {b}^{3} = (a - b)( {a}^{2} + ab + {b}^{2} )$

Answer 2

Answer:

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