factorization of 18x^2- 153x + 280
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Answer:
( 3x - 8 )( 6x - 35 )
Step-by-step explanation:
Given polynomial : 18x^2 - 153x + 280
Factorization by splitting its middle term : -
= > 18x^2 - 153x + 280
Spitting the middle term of the polynomial ( that is 153, numeric co efficient ) in two number such that their product becomes equal to the product of the numeric co efficient of other term( that are 18 { with x^2 } and 280{ with xy }.
So,
153 = 105 + 48, as the product of 18 and 280 is equal to the product of numeric co efficient of other terms,
= > 18x^2 - 153x + 280
= > 18x^2 - ( 105 + 48 )x + 280
= > 18x^2 - 105x - 48x - 280
= > 3x( 6x - 35 ) - 8( 6x - 35 )
= > ( 3x - 8 )( 6x - 35 )
Hence,
18x^2 - 153x + 280 in factorized of product form is ( 3x - 8 )( 6x - 35 ).
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