Math, asked by suyash1411, 1 year ago

factorization of 18x^2- 153x + 280

Answers

Answered by Harsh0026
1
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Answered by abhi569
0

Answer:

( 3x - 8 )( 6x - 35 )


Step-by-step explanation:

Given polynomial : 18x^2 - 153x + 280


Factorization by splitting its middle term : -

= > 18x^2 - 153x + 280


Spitting the middle term of the polynomial ( that is 153, numeric co efficient ) in two number such that their product becomes equal to the product of the numeric co efficient of other term( that are 18 { with x^2 } and 280{ with xy }.

So,

153 = 105 + 48, as the product of 18 and 280 is equal to the product of numeric co efficient of other terms,


= > 18x^2 - 153x + 280

= > 18x^2 - ( 105 + 48 )x + 280

= > 18x^2 - 105x - 48x - 280

= > 3x( 6x - 35 ) - 8( 6x - 35 )

= > ( 3x - 8 )( 6x - 35 )


Hence,

18x^2 - 153x + 280 in factorized of product form is ( 3x - 8 )( 6x - 35 ).

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