Factorization of 8(x+y)^3- 27(x - y)^3
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Answer:
8(x+y)³-27(x-y)³
=8(x+y)³-27(x-y)³8(x+y)³-27(x-y)³
=(-x+5y)(19x²-10xy+7y²)
Step-by-step explanation:
Given
8(x+y)³-27(x-y)³
= [2(x+y)]³-[3(x-y)]³
=(2x+2y)³-(3x-3y)³
thanks
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