Question

Factorization of (l+m) square - 4 lm





​

Answer 1

Answer:

(l+m)² -4lm

l² + m² + 2lm -4lm

l²+m² -2lm

= (l-m)²

Answer 2

Answer:

${(l + m)}^{2} - 4lm$

${l}^{2} + {m}^{2} + 2lm \: - 4 lm$

${l}^{2} + m ^{2} \: - 2lm$

( l + m)²