factorization of the polynomial
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(ax-ay+bx+by)sq :-) c)
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Answer:
Step-by-step explanation:
let x-y=m and x+y=n
so, (x-y)²a²+2(x-y)(x+y)ab+(x+y)²b²
=m²a²+2mnab+n²b²
=(ma)²+2(mn)(ab)+(nb)²
=(ma+nb)²
=(ma+nb)(ma+nb)
=[(x-y)a+(x+y)b][(x-y)a+(x+y)b]
=(ax-ay+bx+by)(ax-ay+bx+by)
=(ax-ay+bx+by)²
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