Question

factorization of the polynomial​

Answer 1

(ax-ay+bx+by)sq :-) c)

Answer 2

Answer:

Step-by-step explanation:

let x-y=m and x+y=n

so, (x-y)²a²+2(x-y)(x+y)ab+(x+y)²b²

=m²a²+2mnab+n²b²

=(ma)²+2(mn)(ab)+(nb)²

=(ma+nb)²

=(ma+nb)(ma+nb)

=[(x-y)a+(x+y)b][(x-y)a+(x+y)b]

=(ax-ay+bx+by)(ax-ay+bx+by)

=(ax-ay+bx+by)²