Question

Factorization of the polynomial
(x-y)²a² + 2(x - y) (x + y)ab + (x + y)²b² gives
(a) (ax-by) (ax + by)
(b) (ax + by) (bx + ay)
c) (ax - ay + bx + by)²
d) (ax + ay + bx + by)²

please guys for my sake answer with steps​

Answer 1

Answer:

The correct answer is c) (ax - ay + bx + by)²

Step-by-step explanation:

$we \: have \\ a {}^{2} + 2ab + b {}^{2} \: equals \: (a + b) {}^{2} \\ similarly \\ (x - y) {}^{2} a {}^{2} + 2(x - y)(x + y)ab + (x + y) {}^{2} b { }^{2} equals \\ ((x - y)a + (x + y)b) {}^{2} \\ (ax - ay + bx + by) {}^{2}$

Answer 2

Answer:

Sorry I don't know