Math, asked by anubrata68, 6 months ago

factorization of x^3-x^2-2x​

Answers

Answered by MightyTheLegend
1

Answer:

x(x-2)(x+1)\\

Step-by-step explanation:

x^3-x^2-2x\\

Factor x out of x^3-x^2-2x\\

=x(x^2-x-2)\\=x(x^2-2x+x-2)\\=x[x(x+1)-2(x+1)]\\=x(x-2)(x+1)

Answered by jaydip1118
1

Answer:

\begin{gathered}x(x-2)(x+1)\\\end{gathered}

x(x−2)(x+1)

Step-by-step explanation:

\begin{gathered}x^3-x^2-2x\\\end{gathered}

x

3

−x

2

−2x

Factor x out of \begin{gathered}x^3-x^2-2x\\\end{gathered}

x

3

−x

2

−2x

∴\begin{gathered}=x(x^2-x-2)\\=x(x^2-2x+x-2)\\=x[x(x+1)-2(x+1)]\\=x(x-2)(x+1)\end{gathered}

=x(x

2

−x−2)

=x(x

2

−2x+x−2)

=x[x(x+1)−2(x+1)]

=x(x−2)(x+1)

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