factorization of x3+ 1 is
Answers
Answered by
10
x³+1
( 1 can be Expressed as 1³)
→ x³+1³
[ Use identity -
x³+y³ = (x+y)(x²-xy+y²]
→ (x+1)(x²-x(1)+1²)
→ (x+1)(x²-x+1)
_______________________________
( 1 can be Expressed as 1³)
→ x³+1³
[ Use identity -
x³+y³ = (x+y)(x²-xy+y²]
→ (x+1)(x²-x(1)+1²)
→ (x+1)(x²-x+1)
_______________________________
Answered by
3
Heya,
Here is the required solution :-
x³ + 1
= x³ + 1³
This is in the form of a³ + b³
⇒ x³ + 1³ = (x+1) [x²-x(1) + 1²
=( x+1) (x² -x + 1)
Hope it helps u........
Here is the required solution :-
x³ + 1
= x³ + 1³
This is in the form of a³ + b³
⇒ x³ + 1³ = (x+1) [x²-x(1) + 1²
=( x+1) (x² -x + 1)
Hope it helps u........
Similar questions