Question

factorization of y²+4y-32​

Answer 1

HerE iS yOuR aNswEr mAte ✨✌️

y²+4y-32 = 0

y²+8y-4y-32 =

y(y+8)-4(y+8)=0

(y+8)(y-4)=0

y=-8,4

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Answer 2

Answer:

y2+8y-4y-32

y(y+8)-4(y+8)

(y-4)(y+8)