Question

factorization plss do it.​

Answer 1

Answer:

f(x) = x³ - 12x + 9

f'(x) = 3x² - 12

f"(x) = 6x

pada f'(x) = 0

3x² - 12 = 0

x² = 4

x = ±√4 = ±2

uji pada f"(x)

x = 2 → 6(2) = 12 (positif) → f"(x) > 0 balik minimum

substitusi pd f(x)

f(2) = 2³ - 12(2) + 9 = -7 (nilai ekstrim minimum)