Question

factorization
${( {2a}^{3} - {b}^{3} ) }^{3} - { {(b}^{3}) }^{3}$
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Answer 1

Answer:

the answer is written below

Step-by-step explanation:

using identity $a^3 - b^3 = (a - b)*(a^2 + ab + b^2)$,

(2a³ - b³)³ - (b³)³ = (2a³ - b³ - b³)*[(2a³-b³)² + (2a³-b³)*b³ + (b³)²]

⇒ (2a³-2b³) (2a⁶ - 4a³b³ + b⁶ + 2a³b³ - b⁶ + b⁶)

⇒  (2a³-2b³) ( 2a⁶ - 2a³b³ + b⁶)

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