Question

factorization
$x {}^{2} - (1 + \sqrt{2} )x + \sqrt{2} = 0$
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Answer 1

Step-by-step explanation:

x² - (1+√2)x + √2

= x² - x + √2x + √2

= x² + √2x - x + √2

= x (x + √2) - 1(x+√2)

= (x - 1) (x+√2)

If you want the values of x then by applying zero product rule,

x - 1 = 0 x + √2 = 0

x = 1 x = - √2

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