Question

Factorize

1) 24p^3q^2+28p^2q^3

2)81a^2-72ab+16b^2​

Answer 1

Answer:

2)

$81 {a}^{2} - 72ab + 16 {b}^{2}$

${(a - b)}^{2} = {a}^{2} - 2ab + {b}^{2}$

${(9a)}^{2} - 2 \times 9a \times 4b + {(4b)}^{2}$

$= > {(9a - 4b)}^{2}$

1)

$24 {p}^{3} {q}^{2} + 28 {p}^{2} {q}^{3}$

$= > 4 {p}^{2} {q}^{2} (6p + 7q)$

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