Question

factorize 1 - 25(2x - 3y)²​

Answer 1

Answer:

1−25(2−3)2

1-25\left(2x-3y\right)^{2}1−25(2x−3y)2

1−25(2−3)(2−3)

Answer 2

Given : The given algebraic expression is, 1 - 25(2x - 3y)²

To find : Factorisation of the given algebraic expression.

Solution :

We can simply solve this mathematical problem by using the following mathematical process. (our goal is to factorise the given algebraic expression)

Here, we will be using algebraic identities in order to factorise the given algebraic expression.

So,

= 1 - 25(2x - 3y)²

= 1 - (5)² × (2x - 3y)²

= 1 - [5 × (2x - 3y)]²

= 1 - (10x - 15y)²

= (1)² - (10x - 15y)²

= (1 + 10x - 15y) (1 - 10x + 15y)

[This cannot be further factorised. That's why this will be considered as the final result of the given mathematical problem.]

Used algebraic identity :

• a²-b² = (a+b) (a-b)

Hence, the answer to the given factorisation is, (1 + 10x - 15y) (1 - 10x + 15y)