factorize 1 -27xcube
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2
first of all, let's find it's cuberoot.
cuberoot of 1 = 1 since 1 × 1 × 1 = 1
cuberoot of 27x³ = (3x)³
therefore final ans = (1)³ - (3x)³
Answered by
3
Answer:
Step-by-step explanation:
1-27x^3
Using
a^3-b^3 = (a-b)(a^2+b^2+ab)
(1)^3-(3x)^3 = (1-3x)(1+9x^2+3x)
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