Factorize :
(1) 343a' – 729b
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This can be written as
343a-729b
=(7a³) - (9b³)
take it in a³-b³
=(a-b)(a²+ab+b²)
=(7a-9b) {(7a)²+7a×9b+(9b)²}
=(7a-9b) (49a²+63ab+81b²)
shivani114055:
thanx
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Answer:
Step-by-step explanation:
The question is wrong it should be 343a^3-729b^3. Ans. (7a)^3-(9b)^3
a^3-b^3=(a+b)^3+3ab(a-b)
Put value(7a-9b)^3*7a*9b(7a-9b)
Take 7a-9b common
(7a-9b) [(7a-9b)^2+189ab]
(7a-9b)(49a^2+81b^2+63ab
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