Question

factorize :-

1/64a^3+b^3+125c^3-15/4abc

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Answer 1

Given: The expression 1/64a^3+b^3+125c^3-15/4abc

To find: Factorise the given equation?

Solution:

• Now we have given the term as  1/64a^3+b^3+125c^3-15/4abc

• We can rewrite it as:

                      a^3/64 + b^3 + 125c^3 - 15abc/4 = (a/4)^3 + b^3 + (5c)^3 - 3 × (a/4) × b × (5c)

• Simplifying it, we get:

                       (a + b + c)((a/4)^2 + b^2 + (5c)^2 - (a/4) × b - b × (5c) - (5c) × (a/4))

                       (a + b + c)(a^2/16 + b^2 + 25c^2 - ab/4 - 5bc - 5ac/4)

Answer:

             So after factorization it comes out to be:

               (a + b + c)(a^2/16 + b^2 + 25c^2 - ab/4 - 5bc - 5ac/4)