Question

factorize: 1 - 64a^3
please can anyone solve this ...please

Answer 1

Answer:

Identity used = a^3-b^3= (a-b)(a^2+b^2+ab)

1 - 64a^3

(1)^3 - (4a)^3

(1-4a){1^2+(4a)^2 + 1×4a}

(1-4a)(1+16a^2+4a)

hope it helps you

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