Question

Factorize 1 + 64a^3 using suitable identity

Answer 1

this is your answer please mark is brainless

Answer 2

$\huge\purple{\mid{\fbox{\tt{Solution:-}}\mid}}$

$1 - {64a}^{3}$

$= {(1)}^{3} + {( - 4a)}^{3} + 3(1)( - 4a)(1 - 4a)$

$=1 - {64a}^{3} - 12a(1 - 4a)$

$=1 - {64a}^{3} - 12a + {48a}^{2}$

$\small\pink{\mid{\fbox{\tt{Hope it's helpful uh ♡♡}}\mid}}$