Question

factorize 1-64a3-12a+48a2​

Answer 1

Answer:

−64a

3

−12a+48a

2

=(1)

3

−(4a)

3

−3(1)

2

(4a)+3(1)(4a)

2

Suitable identities is x

3

−y

3

−3x

2

y+3xy

2

=(x−y)

3

∴(1)

3

−(4a)

3

−3(1)

2

(4a)+3(1)(4a)

2

=(1−4a)

3